Henderson-Hasselbalch Calculator

A tenfold ratio moves the pH by exactly one unit, which is what fixes the useful range.

Clear
Base to acid ratio3 : 1
Buffer pH7.677
pKa used7.2Dihydrogen / hydrogen phosphate
Buffer capacity here0.17269 mol/L per pH unit
Best capacity this system can reach0.23026 at pH 7.2capacity peaks where the two components are equal
Useful range6.2 to 8.2one pH unit each way, which is a 10:1 ratio at either end
This buffer is 0.48 pH units off its pKa, so it has more of one component than the other and will absorb one direction better than the other.

The formula

pH = pKa + log10([A-] / [HA])

Why equal amounts land on the pKa

When the conjugate base and the weak acid are present in equal concentration their ratio is one, the logarithm of one is zero, and the pH sits exactly at the pKa. The concentrations themselves drop out entirely: a 1 M and a 0.01 M acetate buffer mixed one-to-one both read 4.76.

What the concentrations do change

They set the capacity. A dilute buffer holds the same pH but surrenders it after a few drops of acid; a concentrated one absorbs far more before moving. Capacity peaks at the pKa and falls away quickly on either side, which is what fixes the working range at roughly one pH unit each way.

Which denominator?

Most of the confusion in solution work is not arithmetic but bookkeeping. Molarity divides by the volume of the finished solution; molality divides by the mass of the solvent; percent by mass divides by the mass of the solution again. The three agree closely in dilute water and diverge sharply in concentrated acid, which is why a bottle labelled 98 % is also labelled 18.4 M without contradiction.